If f(2tanx/1 tan^2x)=(1 cos2x)(sec^2x 2tanx)/2 then f(4)= 136355

 Transcript Ex 72, 25 1 2 1 tan 2 Step 1 Let 1 tan = Differentiating both sides 0 sec 2 = sec 2 = = sec 2 = 1 cos 2 = cos 2 Step 2 Integrating the function 1 2 1 tan 2Share with your friends Share 02 tan x = 2 ( sin x )/ ( cos x ) (1) = 2 ( sin x )( cos x )/ (cos²x ) = ( sin 2x ) (sec²x ) ( Since, 1/ cos²x = sec²x ) = ( sin 2x

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If f(2tanx/1 tan^2x)=(1 cos2x)(sec^2x 2tanx)/2 then f(4)=

If f(2tanx/1 tan^2x)=(1 cos2x)(sec^2x 2tanx)/2 then f(4)=-Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and more Transcript Example 28 If tan⁡𝑥 = 3/4 , "π" < 𝑥 < 3𝜋/4 , find the value of sin 𝑥/2 , cos 𝑥/2 and tan 𝑥/2 Given that "π" < x < 3𝜋/2 ie180° < x < 3/2 × 180° ie 180° < x < 270° Dividing by 2 all sides (180°)/2 < 𝑥/2 < (270°)/2 90° < 𝑥/2 < 135° So, 𝑥/2 lies in 2nd quadrant In 2nd quadrant, sin is

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 Prove $$\frac{2\tan x}{1\tan^2x}\frac1{2\cos^2x1} = \frac{\cos x\sin x}{\cos x\sin x}$$ I know how to solve it, yet I can't!Verify that $$ 2\cos^2x1 = \frac{1\tan^2x}{1\tan^2x}$$ Stack Exchange Network Stack Exchange network consists of 178 Q&A communities including Stack Overflow , the largest, most trusted online community for developers to learn, share their knowledge, and build their careersI need to use the fact that $\tan 2x=\sin2x \ /\cos2x$ to prove that $$\tan 2x=\frac{2\tan x}{1\tan^2x}$$ I don't know where to start Please help or hint Thanks in advance

Tan2x1 = sec2x sin 2x = 2 sin x cos x cos 2x = 2 cos2x 1 tan x = sin x cos x sec x = 1 cos x cot x = cos x sin x csc x = 1 sin x Some integration formulas R xn dx = xn1 n1 C R 1 x dx = lnjxjC R ex dx = ex C R sin x dx = cos x C R cos x dx = sin xC RB) (tanx 1)(tanx1)/1 tan^2(x) = (sinx/cosx 1)(sinx/cosx 1) / 1 Use trig identities 1 tan^2 x = 1/cos^2 x = sec^2 x (1 tan x) = 1 tan^2 x 2tan x = sec^2 x 2tan x

Something went wrong Wait a moment and try again Try again Please enable Javascript and refresh the page to continueI am unable to see why $$1 \tan^2 x= 1/\cos^2x$$ I have looked into the topic anad I am familiar with the reciprocal ratios of cosec, sec, and cot but cannot derive how this statement makes sense Any help on the topic would be very much appreciatedSimplify (1tan(x)^2)(1sin(x)^2) Rearrange terms Apply pythagorean identity Rewrite in terms of sines and cosines Simplify the expression Tap for more steps Apply the product rule to One to any power is one Apply pythagorean identity Cancel the common factor of

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Sec ( x) − 2 = 0 sec ( x) 2 = 0 Add 2 2 to both sides of the equation sec ( x) = 2 sec ( x) = 2 Take the inverse secant of both sides of the equation to extract x x from inside the secant x = arcsec ( 2) x = arcsec ( 2) The exact value of arcsec ( 2) arcsec ( 2) is π 3 π 3 x = π 3 x = π 3RHs = (2 tan x cos 2 x 1 ) cos 2 x = 2 sin x cos x 1 = 1 sin 2 x If sin 2 x = t, then we have f t = 1 t, where t = sin 2 x where − 1 ≤ t ≤ 1 ∴ Domain is − 1, 1 Adding 1 throughout, 0 ≤ 1 t ≤ 2 or 0 ≤ f (t) ≤ 2 ∴ Range of f(t) is 0, 2Click here👆to get an answer to your question ️ If f(x) = cos^2x sec^2x , then

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A 1 Tan X Tan X 1 Show That A Ta 1 Cos 2x Sin 2x Sin 2x Cos 2x Sarthaks Econnect Largest Online Education Community

  Use the fact that tanx = sinx cosx and sin2x = 2sinxcosx So 2 sinx cosx ⋅ 1 1 sinx cos2x = 2sinxcosx 2 sinx cosx ⋅ cos2x cos2x sin2x = 2sinxcosx 2 sinx cosx ⋅ cos2 x cos2x sin2x = 2sinxcosxTRIGONOMETRIC EQUATIONS An equation involving one or more trigonometrical ratios of unknown angle is called a trigonometric equation eg cos 2 x – 4 sin x = 1 It is to be noted that a trigonometrical identity is satisfied for every value of the unknown angle where as trigonometric equation is satisfied only for some values (finite or infinite) of unknown angleThe distance between 0 0 and 1 1 is 1 1 Divide 2 π 2 π by 1 1 The period of the sec ( x) sec ( x) function is 2 π 2 π so values will repeat every 2 π 2 π radians in both directions The final solution is all the values that make (tan(x)−1)(sec(x)− 1) = 0 ( tan ( x) 1) ( sec ( x) 1) = 0 true

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 Get an answer for 'verify (1 tan^2x)/(tan^2x) = csc^2x' and find homework help for other Math questions at eNotesSolve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and moreB = rsinθ r = √ (a²b²) θ = tan^1 (b/a) → make sure # and < are in right quadrant demoivres theorem if z = r (cosθ isinθ) then z⁹ = r⁹ (cos9θ isin9θ) if you want to find square root plug in 1/2 for n multiply/divide complex # z₁z₂ = r₁r₂ (cos (θ₁θ₂) isin (θ₁θ₂)) z₁/z₂ = r₁/r₂ (cos (θ₁

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Trigonometry Solve for x tan (2x)= (2tan (x))/ (1tan (x)^2) tan (2x) = 2tan (x) 1 − tan2 (x) tan ( 2 x) = 2 tan ( x) 1 tan 2 ( x) Since x x is on the right side of the equation, switch the sides so it is on the left side of the equation 2tan(x) 1− tan2(x) = tan(2x) 2 tan ( x) 1 tan 2 ( x) = tan ( 2 x)Move 1 1 to the left side of the equation by subtracting it from both sides cos2(x) sin4(x) cos2(x) 1 = 0 cos 2 ( x) − sin 4 ( x) cos 2 ( x) − 1 = 0 Simplify with factoring out Tap for more steps Move 1 − 1 cos 2 ( x) 1 sin 4 ( x) cos 2 ( x) = 0 cos 2 ( x) − 1 − sin 4 ( x) cos 2 ( x) = 0 Use the identities $1 tan^2(x)=sec^2(x)$, $1cot^2(x)=cosec^2(x)$ and the definitions of the reciprocal trig functions This will give the answers up to an unknown sign, for which we need to known whether x is obtuse or acute

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Introduction to Tan double angle formula let's look at trigonometric formulae also called as the double angle formulae having double angles Derive Double Angle Formulae for Tan 2 Theta \(Tan 2x =\frac{2tan x}{1tan^{2}x} \) let's recall the addition formula the opposite side is $$2tanx=2*2=4$$ the adjacent side is $$1tan^2x=12^2=14=3$$ (the negative sign just means it will not be in the first quad ) Using pythagoras the hypotenuse will be Misc 8 Find the value of sin 𝑥/2 , cos 𝑥/2 and tan 𝑥/2 in each of the following tan⁡𝑥 = – 4/3 , 𝑥 in quadrant II Given that x is in quadrant II So, 90° < x < 180° Dividing by 2 all sides (90°)/2 < 𝑥/2 < (180°)/2 45° < 𝑥/2 < 90° So, 𝑥/2 lies in Ist quadrant In 1st quadra

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Weekly Subscription $299 USD per week until cancelled Monthly Subscription $9 USD per month until cancelled Annual Subscription $3999 USD per year until cancelledSee the answer Show transcribed image text Expert Answer 100% (3 ratings) Previous question Next question Transcribed Image Text from this Question Prove the identity sec^2/2 tan x = csc 2xFirst, use the positive value of the ± ± to find the first solution tan ( x) = √ 3 3 tan ( x) = √ 3 3 Next, use the negative value of the ± ± to find the second solution tan ( x) = √ 3 3 tan ( x) = − √ 3 3 The complete solution is the result of both the positive and negative portions of the solution

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(tan^2(x)1)/sec^2 = 12cos^2(x) Mulitiply by cos^2 (sin^2 cos^2)/1 = 1 2cos^2 Add cos^2 sin^2 = 1 cos^2 QED Answer by MathTherapy(9794) (Show Source) tan^4 (x) 1 or (tan^2(x)1)(tan^2x1) then i'm stuck! Ex 34, 8 Find the general solution of the equation sec2 2x = 1 – tan 2x sec2 2x = 1 – tan 2x 1 tan2 2x = 1 – tan2x tan2 2x tan2x = 1 – 1 tan2 2x tan2x = 0 tan 2x (tan2x 1) = 0 Hence We know that sec2 x = 1 tan2 x So, sec2 2x = 1 tan2 2x tan 2x = 0 taMathtan^2xcot^2x=2/math math\therefore tan^2x\dfrac{1}{tan^2x}2=22/math math\therefore \left(tanx\dfrac{1}{tanx}\right)^2=4/math math\therefore

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Just observe that cos2xtan3x = tan3x sec2x = tan2x ⋅ tanx sec2x ⋅ 2sec2x 2sec2x = tan2x 2sec4x(2tanxsec2x) = tan2x (1 tan2x)2(tan2x) ′, thus the substitution t = tan2x gives ∫cos2xtan3xdx = ∫ t 2(1 t)2 dt Now the rest is clear Share edited Jun 3 '12 at 1656 answered Jun 3 '12 at 1646Question Prove The Identity Sec^2/2 Tan X = Csc 2x This problem has been solved!Click here👆to get an answer to your question ️ Prove that 2tan^1x = cos^1 ( 1 x^21 x^2 )

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Sin(2x) = (2tan(x)) / (1tan^2(x)) *** Start with RHS 2tanx/(1tan^2x) 2tanx/(sec^2x) 2(sinx/cosx)/(1Solve for x sec(x)^22tan(x)=4 Replace the with based on the identity Reorder the polynomial Factor using the AC method Tap for more steps Consider the form Find a pair of integers whose product is and whose sum is In this case, whose product is and whose sum is f(2tanx/1tan 2 x)=(cos2x1) (sec 2 x2tanx)/2 then f(4) is equal to?

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 Explanation sec2x(1 −cos2x) = sec2x −sec2x × cos2x = sec2x − 1 cos2x ×cos2x = 1 tan2x − 1 cos2x × cos2x = 1 tan2x −1 = tan2x Answer link selected by subrita Best answer We have f (2tanx/ (1 tan2x)) = 1/2 (1 cos2x) (sec2x tanx) = 1/2x 2cos2x x (1 tan2x 2tanx) = cos2x x (1 tanx)2 = {cosx x (1 tanx)}2 = (cosx sinx)2 if sinx=7/5 and angle x is in quadrant 2 and cos y=12/13 and angle y is in quadrant 1 find sin (xy) asked in TRIGONOMETRY by harvy0496 Apprentice doubleangle

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 But is it equal to (2tanx/1tan^2x)^2 is what I'm asking I may have been unclearYou can put this solution on YOUR website!Prove as an identity;

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 Precalculus help I have two problems I am stuck on, if you could show me how to solve the problems it would be much appreciated 1) Find sin 2x, cos 2x, and tan 2x from the given information tan x = − 1/6, cos x > 0 sin 2x = cos 2x = tan 2x =Get an answer for 'Prove the following sin 2x = (tan x)(1 cos 2x)' and find homework help for other Math questions at eNotesFirst I join fractions (Easy) then I "express" tans in

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